A problem about choose one model

Support
1

There is a request,a widget has two models,the code look like this

vtkNew<vtkRender> renderA;
//...
vtkNew<vtkRender> renderB;
//...

renderA->SetViewport(0.0, 0.0, 0.5, 1.0);
renderB->SetViewport(0.5, 0.0, 1.0, 1.0);

//use vtk in a Qt project
vtkNew<vtkGenericOpenGLRenderWindow> renderWindow;
renderWindow->AddRenderer(renderA);
renderWindow->AddRenderer(renderA);

//widget_vtk is a object of class QVTKOpenGLNativeWidget
widget_vtk->setRenderWindow(renderWindow);
renderWindow->Render();

And then,there are two models in the widget,the left is A, and the right is B. When user mouseclick the left half of widget , i need to know user had choosed A;

And When user mouseclick the right half of widget ,i need to know user had choosed B;

So i implement this function by vtkCommand,like this

public ClickCMD : public vtkCommand{
//.....
virtual Execute(vtkObject* caller, unsigned long eventId, void* vtkNotUsed(callData))override;
};

//.cpp

void ClickModelCMD::Execute(vtkObject* caller, unsigned long eventId, void* vtkNotUsed(callData)) {
	if (eventId == vtkCommand::LeftButtonPressEvent) {
		std::cout << "MouseLeftClick" << std::endl;
}

//Qt  project
vtkNew<ClickCMD > clickCMD ;
widget_vtk->renderWindow()->GetInteractor()->AddObserver(vtkCommand::LeftButtonPressEvent, clickModelCMD);

When i exectue those codes , and click any place of widget(QVTKOpenGLNativeWidget),the termintal awalys show “MouseLeftClick”

But there is a problem,there are two model in widget, how can i know that user click A or B? The only way i can think about is use QMouseEvent(Qt Event),through the QPoint to judge that user click A or B.

Now there are only two models in the same weidget,if i need show more models in the same widget ,this way is not a good idea;

So do you have other better way to know whick model is selected by user click?

2

examples.vtk.org/site/Cxx/Picking/HighlightPickedActor/
It looks like a pickup-related function. This example may help you.

3

thank you